Hello

Please see the function given in ex. 3.1

then see the code (part of it describe the function)

(marked in yellow mean 0.25x^2)

according to the following derivative

the code should be

`# function f(x)`

`f = 0.5*x**2+3`

or

`f = (x**2)/2+3`

and not

`f = (x/2)**2+3`

which will result in `df=0.5*x+3`

Is my small penny analysis here is correct?

If so, please correct the notebook.

If not, sorry for the trouble.

Thank you